SAT-42: The Remainder Theorem and the Factor Theorem
Use P(a) to find the remainder when dividing by (x − a), and to test whether (x − a) is a factor.
SAT-42: The Remainder Theorem and the Factor Theorem
Description: In SAT-41 you divided polynomials the long way. These two theorems let you get the same information by just plugging in a number — no long division needed.
The Remainder Theorem
If you divide a polynomial P(x) by (x − a), the remainder is exactly P(a).
So to find a remainder, you don't divide — you evaluate. (Oʻzbekcha: P(x) ni (x − a) ga boʻlgandagi qoldiq — bu P(a) qiymati.)
The Factor Theorem
(x − a) is a factor of P(x) if and only if P(a) = 0.
This is just the special case where the remainder is 0: no remainder means it divides evenly. (Oʻzbekcha: agar P(a) = 0 boʻlsa, (x − a) — P(x) ning koʻpaytuvchisi.)
Worked Example (remainder)
Find the remainder when P(x) = x3 − 2x2 + 5 is divided by (x − 2).
- Here a = 2. Compute P(2) = 23 − 2(2)2 + 5 = 8 − 8 + 5 = 5.
- The remainder is 5 (no division required).
Worked Example (factor)
Is (x − 1) a factor of P(x) = x3 + 2x − 3?
- Compute P(1) = 1 + 2 − 3 = 0. Since P(1) = 0, yes, (x − 1) is a factor.
(Oʻzbekcha: P(1) = 0 boʻlgani uchun (x − 1) koʻpaytuvchi ekan.)
Practice
What is the remainder when P(x) = 2x2 + 3x − 4 is divided by (x + 1)?
Show answer
(x + 1) means a = −1. P(−1) = 2(1) + 3(−1) − 4 = 2 − 3 − 4 = −5.
Key words — Kalit soʻzlar
- Polynomial — koʻphad
- Remainder Theorem — qoldiq haqidagi teorema
- Factor Theorem — koʻpaytuvchi haqidagi teorema
- Remainder — qoldiq
- Factor — koʻpaytuvchi
- Evaluate — qiymatini hisoblash
- Divide evenly — qoldiqsiz boʻlinish
- Root — ildiz
- If and only if — faqat va faqat shu holda
Summary
- Remainder Theorem: remainder of P(x) ÷ (x − a) is P(a).
- Factor Theorem: (x − a) is a factor ⇔ P(a) = 0.
- Watch the sign: dividing by (x + 1) means a = −1.