SAT-80: Completing the Square to Find a Circle's Center and Radius
Turn an expanded circle equation into standard form by completing the square for x and for y.
SAT-80: Completing the Square to Find a Circle's Center and Radius
Description: Sometimes a circle is given expanded, like x2 + y2 + 6x − 4y − 3 = 0, hiding its center and radius. Completing the square for x and for y rewrites it into the standard form of SAT-79 so you can read them off.
Completing the square — the move
For a group like x2 + bx, take half of b, square it, and add it to make a perfect square: x2 + bx + (b/2)2 = (x + b/2)2. Whatever you add on one side you must balance on the other. (Oʻzbekcha: x² + bx ni toʻliq kvadratga keltirish uchun (b/2)² ni qoʻshamiz.)
The plan for a circle
- Group the x-terms together and the y-terms together; move the constant to the right side.
- Complete the square for x, and separately for y (add the same amounts to the right side).
- Write each group as a square; read center (h, k) and radius √(right side).
(Oʻzbekcha: x va y hadlarini alohida guruhlab, har birini toʻliq kvadratga keltiramiz.)
Worked Example 1 — full process
Find the center and radius of x2 + y2 + 6x − 4y − 3 = 0.
- Group: (x2 + 6x) + (y2 − 4y) = 3.
- x: half of 6 is 3, squared is 9. y: half of −4 is −2, squared is 4. Add both to each side.
- (x2 + 6x + 9) + (y2 − 4y + 4) = 3 + 9 + 4 = 16.
- (x + 3)2 + (y − 2)2 = 16 → center (−3, 2), radius √16 = 4.
Worked Example 2 — only one variable needs work
Find the center and radius of x2 + y2 − 10x + 9 = 0.
- Group: (x2 − 10x) + y2 = −9.
- x: half of −10 is −5, squared is 25. Add 25 to both sides.
- (x − 5)2 + y2 = −9 + 25 = 16 → center (5, 0), radius 4.
(Oʻzbekcha: y allaqachon toʻliq kvadrat, faqat x bilan ishlaymiz.)
Worked Example 3 — read the radius carefully
After completing the square a circle becomes (x − 1)2 + (y + 3)2 = 20. State its center and radius.
- Center = (1, −3). Radius = √20 = 2√5 ≈ 4.47.
Trap: forgetting to add the new constants to the right side too. The equation must stay balanced, or the radius comes out wrong. (Oʻzbekcha: qoʻshilgan sonlarni oʻng tomonga ham qoʻshishni unutmang — muvozanat saqlanishi kerak.)
Practice 1
Find the center and radius of x2 + y2 + 8x + 2y + 8 = 0.
Show answer
(x2 + 8x) + (y2 + 2y) = −8. Add 16 and 1: (x + 4)2 + (y + 1)2 = 9. Center (−4, −1), radius 3.
Practice 2
Find the center and radius of x2 + y2 − 6y = 0.
Show answer
x2 + (y2 − 6y) = 0. Add 9: x2 + (y − 3)2 = 9. Center (0, 3), radius 3.
Key words — Kalit soʻzlar
- Complete the square — toʻliq kvadratga keltirish
- Standard form — standart koʻrinish
- Expanded form — yoyilgan koʻrinish
- Perfect square — toʻliq kvadrat
- Center — markaz
- Radius — radius
- Group (terms) — guruhlash (hadlar)
- Balance (the equation) — muvozanat (tenglama)
- Constant — oʻzgarmas (ozod had)
Summary
- Group x-terms and y-terms; complete the square on each using (half of the coefficient)2.
- Add the new constants to both sides to keep balance.
- Rewrite as (x − h)2 + (y − k)2 = r2, then read center (h, k) and radius √(right side).