Mathematics

SAT-80: Completing the Square to Find a Circle's Center and Radius

Turn an expanded circle equation into standard form by completing the square for x and for y.

SAT-80: Completing the Square to Find a Circle's Center and Radius

Description: Sometimes a circle is given expanded, like x2 + y2 + 6x − 4y − 3 = 0, hiding its center and radius. Completing the square for x and for y rewrites it into the standard form of SAT-79 so you can read them off.

Completing the square — the move

For a group like x2 + bx, take half of b, square it, and add it to make a perfect square: x2 + bx + (b/2)2 = (x + b/2)2. Whatever you add on one side you must balance on the other. (Oʻzbekcha: x² + bx ni toʻliq kvadratga keltirish uchun (b/2)² ni qoʻshamiz.)

The plan for a circle

  1. Group the x-terms together and the y-terms together; move the constant to the right side.
  2. Complete the square for x, and separately for y (add the same amounts to the right side).
  3. Write each group as a square; read center (h, k) and radius √(right side).

(Oʻzbekcha: x va y hadlarini alohida guruhlab, har birini toʻliq kvadratga keltiramiz.)

Worked Example 1 — full process

Find the center and radius of x2 + y2 + 6x − 4y − 3 = 0.

  • Group: (x2 + 6x) + (y2 − 4y) = 3.
  • x: half of 6 is 3, squared is 9. y: half of −4 is −2, squared is 4. Add both to each side.
  • (x2 + 6x + 9) + (y2 − 4y + 4) = 3 + 9 + 4 = 16.
  • (x + 3)2 + (y − 2)2 = 16 → center (−3, 2), radius √16 = 4.

Worked Example 2 — only one variable needs work

Find the center and radius of x2 + y2 − 10x + 9 = 0.

  • Group: (x2 − 10x) + y2 = −9.
  • x: half of −10 is −5, squared is 25. Add 25 to both sides.
  • (x − 5)2 + y2 = −9 + 25 = 16 → center (5, 0), radius 4.

(Oʻzbekcha: y allaqachon toʻliq kvadrat, faqat x bilan ishlaymiz.)

Worked Example 3 — read the radius carefully

After completing the square a circle becomes (x − 1)2 + (y + 3)2 = 20. State its center and radius.

  • Center = (1, −3). Radius = √20 = 2√5 ≈ 4.47.
Trap: forgetting to add the new constants to the right side too. The equation must stay balanced, or the radius comes out wrong. (Oʻzbekcha: qoʻshilgan sonlarni oʻng tomonga ham qoʻshishni unutmang — muvozanat saqlanishi kerak.)

Practice 1

Find the center and radius of x2 + y2 + 8x + 2y + 8 = 0.

Show answer

(x2 + 8x) + (y2 + 2y) = −8. Add 16 and 1: (x + 4)2 + (y + 1)2 = 9. Center (−4, −1), radius 3.

Practice 2

Find the center and radius of x2 + y2 − 6y = 0.

Show answer

x2 + (y2 − 6y) = 0. Add 9: x2 + (y − 3)2 = 9. Center (0, 3), radius 3.

Key words — Kalit soʻzlar

  • Complete the square — toʻliq kvadratga keltirish
  • Standard form — standart koʻrinish
  • Expanded form — yoyilgan koʻrinish
  • Perfect square — toʻliq kvadrat
  • Center — markaz
  • Radius — radius
  • Group (terms) — guruhlash (hadlar)
  • Balance (the equation) — muvozanat (tenglama)
  • Constant — oʻzgarmas (ozod had)

Summary

  • Group x-terms and y-terms; complete the square on each using (half of the coefficient)2.
  • Add the new constants to both sides to keep balance.
  • Rewrite as (x − h)2 + (y − k)2 = r2, then read center (h, k) and radius √(right side).
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